the ion formed by magnesium combines with the ion formed by sulfur in a ratio.\n1:1\n3:2\n2:3\n2:2\nquestion…

Explanation:

Step1: Determine magnesium and sulfur ions

Magnesium (Mg) forms a $Mg^{2 + }$ ion by losing 2 electrons. Sulfur (S) forms a $S^{2 - }$ ion by gaining 2 electrons. To form a neutral compound, the charges must balance. So, the ratio of $Mg^{2 + }$ to $S^{2 - }$ is 1:1.

Step2: Determine aluminum and oxide ions

Aluminum (Al) forms an $Al^{3+}$ ion by losing 3 electrons. Oxide ($O^{2 - }$) has a - 2 charge. To balance the charges, we need 2 aluminum ions ($2\times( + 3)=+6$) and 3 oxide ions ($3\times(-2)= - 6$). So the chemical formula is $Al_{2}O_{3}$.

Answer:

First question: A. 1:1 Second question: E. $Al_{2}O_{3}$