ionic bond dot diagram\ndrag valence electrons and type ionic charges\nto complete the ionic bond dot…

ionic bond dot diagram\ndrag valence electrons and type ionic charges\nto complete the ionic bond dot diagram showing\nelectrons before & after they are lost/gained...\nnacl\nna + cl → na cl\nbefore\nafter\nelectrons\ndrag

ionic bond dot diagram\ndrag valence electrons and type ionic charges\nto complete the ionic bond dot diagram showing\nelectrons before & after they are lost/gained...\nnacl\nna + cl → na cl\nbefore\nafter\nelectrons\ndrag

Answer

Explanation:

Step1: Determine valence electrons of Na

Sodium (Na) has 1 valence electron.

Step2: Determine valence electrons of Cl

Chlorine (Cl) has 7 valence electrons.

Step3: Show electron - transfer

Na loses its 1 valence electron to Cl. Na becomes $Na^+$ (with a +1 ionic charge) and Cl becomes $Cl^-$ (with a - 1 ionic charge) after gaining the electron.

Step4: Draw dot - diagram after bonding

In the dot - diagram after bonding, Na has no valence electrons shown (since it lost its only valence electron) and Cl has 8 valence electrons (a full outer shell after gaining the electron from Na).

Answer:

Before: Na has 1 dot (valence electron), Cl has 7 dots (valence electrons). After: Na has no dots (as it became $Na^+$), Cl has 8 dots (as it became $Cl^-$) and the ionic charges are $Na^+$ and $Cl^-$ respectively.