ionic bonding occurs when a metal transfers one or more electrons to a nonmetal in an effort to attain a…

ionic bonding occurs when a metal transfers one or more electrons to a nonmetal in an effort to attain a stable octet of electrons. for example, the transfer of an electron from sodium to chlorine can be shown by using an arrow. show the transfer of electrons and the formation of ions in the following combinations: 1. k + f 2. mg + cl 3. be + o 4. na + s 5. al + f 6. li + o

ionic bonding occurs when a metal transfers one or more electrons to a nonmetal in an effort to attain a stable octet of electrons. for example, the transfer of an electron from sodium to chlorine can be shown by using an arrow. show the transfer of electrons and the formation of ions in the following combinations: 1. k + f 2. mg + cl 3. be + o 4. na + s 5. al + f 6. li + o

Answer

Explanation:

Step1: Analyze K + F

Potassium (K) is a metal with 1 valence - electron. Fluorine (F) is a non - metal with 7 valence - electrons. K donates its 1 valence - electron to F. $K\cdot\rightarrow K^{+}+e^{-}$; $\cdot\ddot{F}:+e^{-}\rightarrow[:\ddot{F}:]^{-}$

Step2: Analyze Mg + Cl

Magnesium (Mg) is a metal with 2 valence - electrons. Chlorine (Cl) is a non - metal with 7 valence - electrons. Mg donates 1 electron to each of 2 Cl atoms. $Mg\cdot\cdot\rightarrow Mg^{2 + }+2e^{-}$; $2\cdot\ddot{Cl}:+2e^{-}\rightarrow2[:\ddot{Cl}:]^{-}$

Step3: Analyze Be + O

Beryllium (Be) is a metal with 2 valence - electrons. Oxygen (O) is a non - metal with 6 valence - electrons. Be donates 2 electrons to O. $Be\cdot\cdot+\cdot\ddot{O}:\rightarrow[Be]^{2 + }[:\ddot{O}:]^{2 - }$

Step4: Analyze Na + S

Sodium (Na) is a metal with 1 valence - electron. Sulfur (S) is a non - metal with 6 valence - electrons. Two Na atoms each donate 1 electron to S. $2Na\cdot\rightarrow2Na^{+}+2e^{-}$; $\cdot\ddot{S}:+2e^{-}\rightarrow[:\ddot{S}:]^{2 - }$

Step5: Analyze Al + F

Aluminum (Al) is a metal with 3 valence - electrons. Fluorine (F) is a non - metal with 7 valence - electrons. Al donates 1 electron to each of 3 F atoms. $Al\cdot\cdot\cdot\rightarrow Al^{3 + }+3e^{-}$; $3\cdot\ddot{F}:+3e^{-}\rightarrow3[:\ddot{F}:]^{-}$

Step6: Analyze Li + O

Lithium (Li) is a metal with 1 valence - electron. Oxygen (O) is a non - metal with 6 valence - electrons. Two Li atoms each donate 1 electron to O. $2Li\cdot\rightarrow2Li^{+}+2e^{-}$; $\cdot\ddot{O}:+2e^{-}\rightarrow[:\ddot{O}:]^{2 - }$

Answer:

  1. $K\cdot\rightarrow K^{+}+e^{-}$; $\cdot\ddot{F}:+e^{-}\rightarrow[:\ddot{F}:]^{-}$
  2. $Mg\cdot\cdot\rightarrow Mg^{2 + }+2e^{-}$; $2\cdot\ddot{Cl}:+2e^{-}\rightarrow2[:\ddot{Cl}:]^{-}$
  3. $Be\cdot\cdot+\cdot\ddot{O}:\rightarrow[Be]^{2 + }[:\ddot{O}:]^{2 - }$
  4. $2Na\cdot\rightarrow2Na^{+}+2e^{-}$; $\cdot\ddot{S}:+2e^{-}\rightarrow[:\ddot{S}:]^{2 - }$
  5. $Al\cdot\cdot\cdot\rightarrow Al^{3 + }+3e^{-}$; $3\cdot\ddot{F}:+3e^{-}\rightarrow3[:\ddot{F}:]^{-}$
  6. $2Li\cdot\rightarrow2Li^{+}+2e^{-}$; $\cdot\ddot{O}:+2e^{-}\rightarrow[:\ddot{O}:]^{2 - }$