ionic compounds\nif given the formula, give the name and vice versa:\na) cal₂\ncalcium iodide\nb) lead (ii)…

ionic compounds\nif given the formula, give the name and vice versa:\na) cal₂\ncalcium iodide\nb) lead (ii) perchlorate\nc) zinc nitride\nd) cus\ne) copper (ii) nitrate\nf) calcium fluoride\ng) copper (ii) bromide\nh) (nh₄)₂so₃\ni) sr₃(po₄)₂\nj) nh₄cl\nk) titanium (iv) nitride\nl) cu₂o\nm) mg(oh)₂\nn) na₂so₄\no) copper (i) nitride\np) rabr₂\nq) magnesium sulphide\nr) mnbr₃\ns) aluminum nitrate\nt) ammonium sulphate\nu) sodium oxide\nv) na₂o\nw) tin (iv) sulphide\nx) cuo\ny) zinc hydrogen sulphate\nz) fe₂(so₄)₃

ionic compounds\nif given the formula, give the name and vice versa:\na) cal₂\ncalcium iodide\nb) lead (ii) perchlorate\nc) zinc nitride\nd) cus\ne) copper (ii) nitrate\nf) calcium fluoride\ng) copper (ii) bromide\nh) (nh₄)₂so₃\ni) sr₃(po₄)₂\nj) nh₄cl\nk) titanium (iv) nitride\nl) cu₂o\nm) mg(oh)₂\nn) na₂so₄\no) copper (i) nitride\np) rabr₂\nq) magnesium sulphide\nr) mnbr₃\ns) aluminum nitrate\nt) ammonium sulphate\nu) sodium oxide\nv) na₂o\nw) tin (iv) sulphide\nx) cuo\ny) zinc hydrogen sulphate\nz) fe₂(so₄)₃

Answer

Part (b)

Explanation:

Step1: Identify ions

Lead (II) has charge ( \text{Pb}^{2+} ), perchlorate is ( \text{ClO}_4^- ).

Step2: Balance charges

To balance ( 2+ ) and ( 1- ), we need 2 perchlorate ions. So formula is ( \text{Pb(ClO}_4\text{)}_2 ).

Answer: ( \text{Pb(ClO}_4\text{)}_2 )

Part (c)

Explanation:

Step1: Identify ions

Zinc has charge ( \text{Zn}^{2+} ), nitride is ( \text{N}^{3-} ).

Step2: Find LCM of charges (6)

Zinc: ( \frac{6}{2} = 3 ), Nitride: ( \frac{6}{3} = 2 ). So formula is ( \text{Zn}_3\text{N}_2 ).

Answer: ( \text{Zn}_3\text{N}_2 )

Part (d)

Explanation:

Step1: Identify ions

Copper (from CuS, assume Cu²⁺ as S is ( \text{S}^{2-} )), sulfide is ( \text{S}^{2-} ).

Step2: Balance charges

( 2+ ) and ( 2- ) balance, so name is Copper (II) Sulfide.

Answer: Copper (II) Sulfide

Part (e)

Explanation:

Step1: Identify ions

Copper (II) is ( \text{Cu}^{2+} ), nitrate is ( \text{NO}_3^- ).

Step2: Balance charges

2 nitrate ions for 1 copper (II). Formula: ( \text{Cu(NO}_3\text{)}_2 ).

Answer: ( \text{Cu(NO}_3\text{)}_2 )

Part (f)

Explanation:

Step1: Identify ions

Calcium is ( \text{Ca}^{2+} ), fluoride is ( \text{F}^- ).

Step2: Balance charges

2 fluoride ions for 1 calcium. Formula: ( \text{CaF}_2 ).

Answer: ( \text{CaF}_2 )

Part (g)

Explanation:

Step1: Identify ions

Copper (II) is ( \text{Cu}^{2+} ), bromide is ( \text{Br}^- ).

Step2: Balance charges

2 bromide ions for 1 copper (II). Formula: ( \text{CuBr}_2 ).

Answer: ( \text{CuBr}_2 )

Part (h)

Explanation:

Step1: Identify ions

Ammonium is ( \text{NH}_4^+ ), sulfite is ( \text{SO}_3^{2-} ).

Step2: Balance charges

2 ammonium ions for 1 sulfite. Name: Ammonium Sulfite.

Answer: Ammonium Sulfite

Part (i)

Explanation:

Step1: Identify ions

Strontium is ( \text{Sr}^{2+} ), phosphate is ( \text{PO}_4^{3-} ).

Step2: Find LCM (6)

Strontium: ( \frac{6}{2}=3 ), Phosphate: ( \frac{6}{3}=2 ). Formula: ( \text{Sr}_3(\text{PO}_4)_2 ) (name is Strontium Phosphate).

Answer: Strontium Phosphate

Part (j)

Explanation:

Step1: Identify ions

Ammonium ( \text{NH}_4^+ ), chloride ( \text{Cl}^- ).

Step2: Balance charges

1:1 ratio. Name: Ammonium Chloride.

Answer: Ammonium Chloride

Part (k)

Explanation:

Step1: Identify ions

Titanium (IV) ( \text{Ti}^{4+} ), nitride ( \text{N}^{3-} ).

Step2: LCM (12)

Titanium: ( \frac{12}{4}=3 ), Nitride: ( \frac{12}{3}=4 ). Formula: ( \text{Ti}_3\text{N}_4 ).

Answer: ( \text{Ti}_3\text{N}_4 )

Part (l)

Explanation:

Step1: Identify ions

Copper (I) ( \text{Cu}^+ ), oxide ( \text{O}^{2-} ).

Step2: Balance charges

2 copper (I) for 1 oxide. Name: Copper (I) Oxide.

Answer: Copper (I) Oxide

Part (m)

Explanation:

Step1: Identify ions

Magnesium ( \text{Mg}^{2+} ), hydroxide ( \text{OH}^- ).

Step2: Balance charges

2 hydroxide ions for 1 magnesium. Formula: ( \text{Mg(OH)}_2 ) (name is Magnesium Hydroxide).

Answer: Magnesium Hydroxide

Part (n)

Explanation:

Step1: Identify ions

Sodium ( \text{Na}^+ ), sulfate ( \text{SO}_4^{2-} ).

Step2: Balance charges

2 sodium ions for 1 sulfate. Formula: ( \text{Na}_2\text{SO}_4 ) (name is Sodium Sulfate).

Answer: Sodium Sulfate

Part (o)

Explanation:

Step1: Identify ions

Copper (I) ( \text{Cu}^+ ), nitride ( \text{N}^{3-} ).

Step2: LCM (3)

Copper: ( \frac{3}{1}=3 ), Nitride: ( \frac{3}{3}=1 ). Formula: ( \text{Cu}_3\text{N} ).

Answer: ( \text{Cu}_3\text{N} )

Part (p)

Explanation:

Step1: Identify ions

Radium ( \text{Ra}^{2+} ), bromide ( \text{Br}^- ).

Step2: Balance charges

2 bromide ions for 1 radium. Formula: ( \text{RaBr}_2 ) (name is Radium Bromide).

Answer: Radium Bromide

Part (q)

Explanation:

Step1: Identify ions

Magnesium ( \text{Mg}^{2+} ), sulfide ( \text{S}^{2-} ).

Step2: Balance charges

1:1 ratio. Formula: ( \text{MgS} ).

Answer: ( \text{MgS} )

Part (r)

Explanation:

Step1: Identify ions

Manganese (from ( \text{MnBr}_3 ), charge ( \text{Mn}^{3+} )), bromide ( \text{Br}^- ).

Step2: Balance charges

3 bromide ions for 1 manganese (III). Name: Manganese (III) Bromide.

Answer: Manganese (III) Bromide

Part (s)

Explanation:

Step1: Identify ions

Aluminum ( \text{Al}^{3+} ), nitrate ( \text{NO}_3^- ).

Step2: Balance charges

3 nitrate ions for 1 aluminum. Formula: ( \text{Al(NO}_3\text{)}_3 ).

Answer: ( \text{Al(NO}_3\text{)}_3 )

Part (t)

Explanation:

Step1: Identify ions

Ammonium ( \text{NH}_4^+ ), sulfate ( \text{SO}_4^{2-} ).

Step2: Balance charges

2 ammonium ions for 1 sulfate. Formula: ( (\text{NH}_4)_2\text{SO}_4 ).

Answer: ( (\text{NH}_4)_2\text{SO}_4 )

Part (u)

Explanation:

Step1: Identify ions

Sodium ( \text{Na}^+ ), oxide ( \text{O}^{2-} ).

Step2: Balance charges

2 sodium ions for 1 oxide. Formula: ( \text{Na}_2\text{O} ).

Answer: ( \text{Na}_2\text{O} )

Part (v)

Explanation:

Step1: Identify ions

Sodium ( \text{Na}^+ ), oxide ( \text{O}^{2-} ).

Step2: Balance charges

2 sodium ions for 1 oxide. Name: Sodium Oxide.

Answer: Sodium Oxide

Part (w)

Explanation:

Step1: Identify ions

Tin (IV) ( \text{Sn}^{4+} ), sulfide ( \text{S}^{2-} ).

Step2: Balance charges

2 sulfide ions for 1 tin (IV). Formula: ( \text{SnS}_2 ).

Answer: ( \text{SnS}_2 )

Part (x)

Explanation:

Step1: Identify ions

Copper (II) ( \text{Cu}^{2+} ), oxide ( \text{O}^{2-} ).

Step2: Balance charges

1:1 ratio. Name: Copper (II) Oxide.

Answer: Copper (II) Oxide

Part (y)

Explanation:

Step1: Identify ions

Zinc ( \text{Zn}^{2+} ), hydrogen sulfate ( \text{HSO}_4^- ).

Step2: Balance charges

2 hydrogen sulfate ions for 1 zinc. Formula: ( \text{Zn(HSO}_4\text{)}_2 ).

Answer: ( \text{Zn(HSO}_4\text{)}_2 )

Part (z)

Explanation:

Step1: Identify ions

Iron (III) ( \text{Fe}^{3+} ), sulfate ( \text{SO}_4^{2-} ).

Step2: LCM (6)

Iron: ( \frac{6}{3}=2 ), Sulfate: ( \frac{6}{2}=3 ). Formula: ( \text{Fe}_2(\text{SO}_4)_3 ) (name is Iron (III) Sulfate).

Answer: Iron (III) Sulfate