lets start by figuring out the amount needed in moles. from there, we can easily find the equivalent mass…

lets start by figuring out the amount needed in moles. from there, we can easily find the equivalent mass. if c = n/ v . which equation do we need to find out how many moles of nh₄cl would there be in 500 ml of a 0.300 m solution of it?\na) c = v / n\nb) n = c x v\nc) n = c / v\nd) c = n x v

lets start by figuring out the amount needed in moles. from there, we can easily find the equivalent mass. if c = n/ v . which equation do we need to find out how many moles of nh₄cl would there be in 500 ml of a 0.300 m solution of it?\na) c = v / n\nb) n = c x v\nc) n = c / v\nd) c = n x v

Answer

Explanation:

Step1: Rearrange the concentration formula

Given $C=\frac{n}{V}$, to solve for $n$ (number of moles), we multiply both sides of the equation by $V$. $C\times V=\frac{n}{V}\times V$

Step2: Simplify the equation

We get $n = C\times V$.

Answer:

B. $n = C\times V$