which lewis dot diagram shows an atom that needs 2 more electrons in its outermost shell?\na\nb\nc\nd\nh…

which lewis dot diagram shows an atom that needs 2 more electrons in its outermost shell?\na\nb\nc\nd\nh •\nhydrogen\na\n• c •\ncarbon\nb\n: o :\noxygen\nc\n: f :\nflourine\nd

which lewis dot diagram shows an atom that needs 2 more electrons in its outermost shell?\na\nb\nc\nd\nh •\nhydrogen\na\n• c •\ncarbon\nb\n: o :\noxygen\nc\n: f :\nflourine\nd

Answer

Explanation:

Step1: Recall octet - rule and valence electrons

Atoms tend to gain, lose, or share electrons to have 8 electrons in their outermost shell (except hydrogen which aims for 2). We need to find the atom with 6 valence electrons as it needs 2 more to complete the octet.

Step2: Analyze each option

  • Hydrogen (A) has 1 valence electron. It needs 1 more to reach a duet.
  • Carbon (B) has 4 valence electrons. It needs 4 more to complete the octet.
  • Oxygen (C) has 6 valence electrons. It needs 2 more to complete the octet.
  • Fluorine (D) has 7 valence electrons. It needs 1 more to complete the octet.

Answer:

C. oxygen