look at the combustion reactions shown below.\n2c₂h₂ + 5o₂ → 4co₂ + 2h₂o\n2c₂h₆ + 7o₂ → 4co₂ + 6h₂o\nc₅h₁₂ +…

look at the combustion reactions shown below.\n2c₂h₂ + 5o₂ → 4co₂ + 2h₂o\n2c₂h₆ + 7o₂ → 4co₂ + 6h₂o\nc₅h₁₂ + 8o₂ → 5co₂ + 6h₂o\n2c₆h₁₄ + 19o₂ → 12co₂ + 14h₂o\nwhat is the same about the first reactant in all of the equations?\nwhat is the same about the second reactant in all of the equations?\nwhat is the same about the first product in all of the equations?\nwhat is the same about the second product in all of the equations?

look at the combustion reactions shown below.\n2c₂h₂ + 5o₂ → 4co₂ + 2h₂o\n2c₂h₆ + 7o₂ → 4co₂ + 6h₂o\nc₅h₁₂ + 8o₂ → 5co₂ + 6h₂o\n2c₆h₁₄ + 19o₂ → 12co₂ + 14h₂o\nwhat is the same about the first reactant in all of the equations?\nwhat is the same about the second reactant in all of the equations?\nwhat is the same about the first product in all of the equations?\nwhat is the same about the second product in all of the equations?

Answer

Explanation:

Step1: Analyze first reactant

All first reactants are hydrocarbons (compounds of carbon and hydrogen).

Step2: Analyze second reactant

All second reactants are oxygen ($O_2$).

Step3: Analyze first product

All first products are carbon - dioxide ($CO_2$).

Step4: Analyze second product

All second products are water ($H_2O$).

Answer:

  1. They are all hydrocarbons.
  2. They are all oxygen.
  3. They are all carbon - dioxide.
  4. They are all water.