how many grams of co would be required to generate 635 g co₂?\nfe₂o₃ + 3co → 2fe + 3co₂\nco : 28.01…

Explanation:

Step1: Calculate the number of moles of (CO_2)

The formula for the number of moles (n=\frac{m}{M}), where (m) is the mass and (M) is the molar mass. Given (m(CO_2) = 635\space g) and (M(CO_2)=44.01\space g/mol) (n(CO_2)=\frac{635\space g}{44.01\space g/mol}\approx14.43\space mol)

Step2: Use the stoichiometric ratio from the balanced equation

From the balanced equation (Fe_2O_3 + 3CO\rightarrow2Fe+3CO_2), the ratio of (n(CO)) to (n(CO_2)) is (1:1) (since the coefficients of (CO) and (CO_2) are both (3)). So (n(CO)=n(CO_2) = 14.43\space mol)

Step3: Calculate the mass of (CO)

Using the formula (m = n\times M), with (n(CO)=14.43\space mol) and (M(CO) = 28.01\space g/mol) (m(CO)=14.43\space mol\times28.01\space g/mol\approx404\space g)

Answer:

(404\space g)