how many grams of kmno4 are needed to make 0.500 l of 1.0 m kmno4 solution? kmno4: 158.03 g/mol
how many grams of kmno4 are needed to make 0.500 l of 1.0 m kmno4 solution? kmno4: 158.03 g/mol
Answer
Explanation:
Step1: Calculate moles of KMnO4
Use the formula $n = M\times V$, where $n$ is the number of moles, $M$ is the molarity, and $V$ is the volume in liters. $n = 1.0\ mol/L\times0.500\ L = 0.500\ mol$
Step2: Calculate mass of KMnO4
Use the formula $m=n\times M_m$, where $m$ is the mass, $n$ is the number of moles, and $M_m$ is the molar - mass. $m = 0.500\ mol\times158.03\ g/mol = 79.015\ g$
Answer:
$79.0\ g$ (rounded to three significant figures)