how many grams of pb would be required to make 119 g h2o? pb + pbo2 + 2h2so4 → 2pbso4 + 2h2o pb : 207.2…

how many grams of pb would be required to make 119 g h2o? pb + pbo2 + 2h2so4 → 2pbso4 + 2h2o pb : 207.2 g/mol h2o : 18.02 g/mol ? g pb

how many grams of pb would be required to make 119 g h2o? pb + pbo2 + 2h2so4 → 2pbso4 + 2h2o pb : 207.2 g/mol h2o : 18.02 g/mol ? g pb

Answer

Answer:

  1. g

Explanation:

Step1: Calculate moles of H₂O

$n_{H_2O}=\frac{m_{H_2O}}{M_{H_2O}}=\frac{119\ g}{18.02\ g/mol}\approx6.60\ mol$

Step2: Determine mole - ratio

From the balanced equation $Pb + PbO_2+2H_2SO_4\rightarrow2PbSO_4 + 2H_2O$, the mole - ratio of $Pb$ to $H_2O$ is 1:2. So, $n_{Pb}=\frac{1}{2}n_{H_2O}$. $n_{Pb}=\frac{1}{2}\times6.60\ mol = 3.30\ mol$

Step3: Calculate mass of Pb

$m_{Pb}=n_{Pb}\times M_{Pb}=3.30\ mol\times207.2\ g/mol\approx690.\ g$