how many grams of pbso4 would be produced from the complete reaction of 23.6 g pbo2? pb + pbo2 + 2h2so4 →…

Explanation:

Step1: Calculate moles of PbO₂

$n_{PbO_2}=\frac{m_{PbO_2}}{M_{PbO_2}}=\frac{23.6\ g}{239.2\ g/mol}$

Step2: Determine mole - ratio

From the balanced equation $Pb + PbO_2+2H_2SO_4\rightarrow2PbSO_4 + 2H_2O$, the mole - ratio of $PbO_2$ to $PbSO_4$ is 1:2. So $n_{PbSO_4}=2\times n_{PbO_2}$

Step3: Calculate mass of PbSO₄

$m_{PbSO_4}=n_{PbSO_4}\times M_{PbSO_4}=2\times\frac{23.6\ g}{239.2\ g/mol}\times303.27\ g/mol$

$m_{PbSO_4}=2\times\frac{23.6}{239.2}\times303.27\ g$ $m_{PbSO_4}=59.0\ g$

Answer:

59.0 g