how many liters of water must be added to 0.291 g of nacl to create a saltwater solution that has a…

how many liters of water must be added to 0.291 g of nacl to create a saltwater solution that has a concentration of 2.41 g/l? use g/l = \\frac{grams of solute}{liter of solution}. 0.121 l 0.701 l 2.12 l 8.28 l
Answer
Explanation:
Step1: Identify the formula variables
We know grams of solute ($m = 0.291$ g) and concentration ($C=2.41$ g/L). We use the formula $C=\frac{m}{V}$, where $C$ is concentration, $m$ is mass of solute and $V$ is volume of solution.
Step2: Rearrange the formula to solve for volume
From $C = \frac{m}{V}$, we can get $V=\frac{m}{C}$.
Step3: Substitute the values
Substitute $m = 0.291$ g and $C = 2.41$ g/L into the formula $V=\frac{m}{C}$, so $V=\frac{0.291}{2.41}$ L. $V = 0.121$ L
Answer:
A. 0.121 L