1) how many milliliters of the approximately 0.11 m prepared copper(ii) sulfate stock solution are needed to…

1) how many milliliters of the approximately 0.11 m prepared copper(ii) sulfate stock solution are needed to prepare 100.00 milliliters of a 0.011 m copper(ii) sulfate solution?

1) how many milliliters of the approximately 0.11 m prepared copper(ii) sulfate stock solution are needed to prepare 100.00 milliliters of a 0.011 m copper(ii) sulfate solution?

Answer

Explanation:

Step1: Identify the dilution formula

The dilution formula is $M_1V_1 = M_2V_2$, where $M_1$ is the initial concentration, $V_1$ is the initial volume, $M_2$ is the final concentration, and $V_2$ is the final volume.

Step2: Assign values

Let $M_1 = 0.11\ M$, $V_2=100.00\ mL$, and $M_2 = 0.011\ M$. We need to find $V_1$.

Step3: Rearrange the formula to solve for $V_1$

$V_1=\frac{M_2V_2}{M_1}$

Step4: Substitute values into the formula

$V_1=\frac{0.011\ M\times100.00\ mL}{0.11\ M}$ $V_1 = 10\ mL$

Answer:

10