how many molecules of methane, ch4, are in 125 g ch4? (1 mol ch4 = 16.04 g) (1 mol ch4 = 6.02 x 10^23…

how many molecules of methane, ch4, are in 125 g ch4? (1 mol ch4 = 16.04 g) (1 mol ch4 = 6.02 x 10^23 molecules) ? x 10^? molecules ch4 enter the coefficient in the green box and the exponent in the yellow box. coefficient (green) exponent (yellow)

how many molecules of methane, ch4, are in 125 g ch4? (1 mol ch4 = 16.04 g) (1 mol ch4 = 6.02 x 10^23 molecules) ? x 10^? molecules ch4 enter the coefficient in the green box and the exponent in the yellow box. coefficient (green) exponent (yellow)

Answer

Explanation:

Step1: Calculate moles of CH4

First, find the number of moles of CH4 using the mass - molar mass relationship. Given mass of CH4 is 125 g and molar mass of CH4 is 16.04 g/mol. The number of moles $n=\frac{m}{M}$, where $m = 125$ g and $M=16.04$ g/mol. So, $n=\frac{125}{16.04}\text{ mol}\approx7.79$ mol.

Step2: Calculate number of molecules

Use Avogadro's number ($N_A = 6.02\times10^{23}$ molecules/mol). The number of molecules $N=n\times N_A$. Substitute $n = 7.79$ mol and $N_A=6.02\times 10^{23}$ molecules/mol. So, $N = 7.79\times6.02\times10^{23}$ molecules. $7.79\times6.02 = 46.9958\approx47.0$.

Answer:

Coefficient (green): 47.0 Exponent (yellow): 23