how many moles of al₂s₃ are equivalent to 605 g al₂s₃? molar mass al₂s₃ = 150.17 g/mol

Explanation:

Step1: Recall the formula for moles

The formula for calculating the number of moles ($n$) is $n=\frac{m}{M}$, where $m$ is the mass and $M$ is the molar mass.

Step2: Substitute the given values

Given $m = 605\ g$ and $M=150.17\ g/mol$. Then $n=\frac{605\ g}{150.17\ g/mol}$.

Step3: Calculate the value

$n=\frac{605}{150.17}\approx4.03\ mol$

Answer:

$4.03\ mol$