how many moles of c6h12o6 are consumed when 6.0 moles o2 are used? c6h12o6 + 6o2 → 6co2 + 6h2o ? mol c6h12o6

Explanation:

Step1: Identify mole - ratio

From the balanced chemical equation $C_{6}H_{12}O_{6}+6O_{2}\rightarrow6CO_{2}+6H_{2}O$, the mole - ratio of $C_{6}H_{12}O_{6}$ to $O_{2}$ is $n_{C_{6}H_{12}O_{6}}:n_{O_{2}} = 1:6$.

Step2: Calculate moles of $C_{6}H_{12}O_{6}$

Let the moles of $C_{6}H_{12}O_{6}$ be $x$. We know $n_{O_{2}}=6.0$ mol. Using the mole - ratio $\frac{n_{C_{6}H_{12}O_{6}}}{n_{O_{2}}}=\frac{1}{6}$, so $x=\frac{1}{6}\times n_{O_{2}}$. Substituting $n_{O_{2}} = 6.0$ mol, we get $x=\frac{1}{6}\times6.0$ mol. $x = 1.0$ mol

Answer:

$1.0$ mol