how many moles of c6h12o6 are consumed when 6.0 moles o2 are used?\nc6h12o6 + 6o2 → 6co2 + 6h2o\n? mol c6h12o6

how many moles of c6h12o6 are consumed when 6.0 moles o2 are used?\nc6h12o6 + 6o2 → 6co2 + 6h2o\n? mol c6h12o6

how many moles of c6h12o6 are consumed when 6.0 moles o2 are used?\nc6h12o6 + 6o2 → 6co2 + 6h2o\n? mol c6h12o6

Answer

Explanation:

Step1: Identify mole - ratio

From the balanced equation $C_{6}H_{12}O_{6}+6O_{2}\rightarrow6CO_{2}+6H_{2}O$, the mole - ratio of $C_{6}H_{12}O_{6}$ to $O_{2}$ is 1:6.

Step2: Calculate moles of $C_{6}H_{12}O_{6}$

Let $x$ be the moles of $C_{6}H_{12}O_{6}$. We know that $\frac{x}{6.0\ mol\ O_{2}}=\frac{1}{6}$. Solving for $x$, we get $x = \frac{1\times6.0\ mol\ O_{2}}{6}=1.0\ mol$.

Answer:

1.0