6. how many moles of chromium(iii) nitrate are produced when chromium reacts with 0.85 moles of lead(iv)…

6. how many moles of chromium(iii) nitrate are produced when chromium reacts with 0.85 moles of lead(iv) nitrate to produce chromium(iii) nitrate and lead?\nword equation:\nformula equation:\n(must be balanced!)

6. how many moles of chromium(iii) nitrate are produced when chromium reacts with 0.85 moles of lead(iv) nitrate to produce chromium(iii) nitrate and lead?\nword equation:\nformula equation:\n(must be balanced!)

Answer

Explanation:

Step1: Write balanced chemical equation

$2Cr + 3Pb(NO_3)_4\rightarrow 2Cr(NO_3)_3+3Pb$

Step2: Determine mole - ratio

The mole - ratio of $Pb(NO_3)_4$ to $Cr(NO_3)_3$ is 3:2.

Step3: Calculate moles of $Cr(NO_3)_3$

Let $n_{Cr(NO_3)_3}$ be the moles of $Cr(NO_3)3$ and $n{Pb(NO_3)4}=0.85$ moles. Using the mole - ratio $\frac{n{Cr(NO_3)3}}{n{Pb(NO_3)4}}=\frac{2}{3}$, so $n{Cr(NO_3)3}=\frac{2}{3}\times n{Pb(NO_3)_4}=\frac{2}{3}\times0.85\approx0.57$ moles.

Answer:

0.57 moles