how many moles of kcl are produced at the same time as 9 moles o2?\n2kclo3 → 2kcl + 3o2\n? mol kcl

Explanation:

Step1: Identify mole - ratio

From the balanced chemical equation $2KClO_3\rightarrow2KCl + 3O_2$, the mole - ratio of $KCl$ to $O_2$ is $\frac{n_{KCl}}{n_{O_2}}=\frac{2}{3}$.

Step2: Calculate moles of KCl

We know $n_{O_2}=9$ moles. Using the mole - ratio, $n_{KCl}=\frac{2}{3}\times n_{O_2}$. Substitute $n_{O_2} = 9$ moles into the equation: $n_{KCl}=\frac{2}{3}\times9$. $n_{KCl}=6$ moles.

Answer:

6