how many moles of n2o5 are needed to produce 7.90 g of no2? 2n2o5 → 4no2 + o2 ? mol n2o5
how many moles of n2o5 are needed to produce 7.90 g of no2? 2n2o5 → 4no2 + o2 ? mol n2o5
Answer
Explanation:
Step1: Calculate moles of NO2
The molar - mass of NO2 is (M_{NO_2}=14 + 2\times16=46\ g/mol). The number of moles of NO2, (n_{NO_2}=\frac{m}{M}), where (m = 7.90\ g) and (M = 46\ g/mol). So (n_{NO_2}=\frac{7.90\ g}{46\ g/mol}\approx0.172\ mol).
Step2: Use mole - ratio from the balanced equation
From the balanced equation (2N_2O_5\rightarrow4NO_2 + O_2), the mole - ratio of (N_2O_5) to (NO_2) is (\frac{n_{N_2O_5}}{n_{NO_2}}=\frac{2}{4}=\frac{1}{2}). We know (n_{NO_2}\approx0.172\ mol), and (n_{N_2O_5}=\frac{1}{2}n_{NO_2}). So (n_{N_2O_5}=\frac{1}{2}\times0.172\ mol = 0.086\ mol).
Answer:
0.086 mol