how many moles of o2 are in a container with a volume of 67 l at stp?
how many moles of o2 are in a container with a volume of 67 l at stp?
Answer
Explanation:
Step1: Recall molar - volume at STP
At STP (Standard Temperature and Pressure), 1 mole of any ideal gas occupies a volume of 22.4 L. Let $n$ be the number of moles of $O_2$ and $V$ be the volume of the gas. The relationship is $V = n\times V_m$, where $V_m=22.4\ L/mol$.
Step2: Solve for the number of moles
We can re - arrange the formula $V = n\times V_m$ to $n=\frac{V}{V_m}$. Given $V = 67\ L$ and $V_m = 22.4\ L/mol$, then $n=\frac{67\ L}{22.4\ L/mol}$. $n=\frac{67}{22.4}\approx 2.99\ mol$
Answer:
2.99 mol