how many moles of oxygen (o2) are present in 33.6 l of the gas at 1 atm and 0°c?\n1.5\n2\n22.4\n32
how many moles of oxygen (o2) are present in 33.6 l of the gas at 1 atm and 0°c?\n1.5\n2\n22.4\n32
Answer
Explanation:
Step1: Recall molar - volume at STP
At standard temperature and pressure (STP: 1 atm and 0°C), the molar volume of any ideal gas is 22.4 L/mol.
Step2: Calculate the number of moles
We use the formula $n=\frac{V}{V_m}$, where $n$ is the number of moles, $V$ is the volume of the gas, and $V_m$ is the molar volume. Given $V = 33.6$ L and $V_m=22.4$ L/mol. Then $n=\frac{33.6}{22.4}$. $n = 1.5$ mol
Answer:
A. 1.5