how many moles of pb(no3)2 are required to generate 12 moles al(no3)3?\n3pb(no3)2 + 2alcl3 → 3pbcl2 +…
how many moles of pb(no3)2 are required to generate 12 moles al(no3)3?\n3pb(no3)2 + 2alcl3 → 3pbcl2 + 2al(no3)3\n? mol pb(no3)2
Answer
Explanation:
Step1: Identify mole - ratio
From the balanced chemical equation $3Pb(NO_3)_2 + 2AlCl_3\rightarrow3PbCl_2 + 2Al(NO_3)_3$, the mole - ratio of $Pb(NO_3)_2$ to $Al(NO_3)3$ is $\frac{n{Pb(NO_3)2}}{n{Al(NO_3)_3}}=\frac{3}{2}$.
Step2: Calculate moles of $Pb(NO_3)_2$
We know $n_{Al(NO_3)3} = 12$ moles. Using the mole - ratio, $n{Pb(NO_3)2}=\frac{3}{2}\times n{Al(NO_3)3}$. Substitute $n{Al(NO_3)3}=12$ moles into the equation: $n{Pb(NO_3)2}=\frac{3}{2}\times12$. $n{Pb(NO_3)_2}=18$ moles.
Answer:
18