how many nitrogen atoms are present in one mole of nh4no3?\n1 mol nh4no3 / 1 * 2 mol n / 1 mol nh4no3 *…

how many nitrogen atoms are present in one mole of nh4no3?\n1 mol nh4no3 / 1 * 2 mol n / 1 mol nh4no3 * 6.02×10^23 atom n / 1 mol n =\n1 atom\n6.02×10^23 atoms\n2 atoms\n1.20×10^24 atoms

how many nitrogen atoms are present in one mole of nh4no3?\n1 mol nh4no3 / 1 * 2 mol n / 1 mol nh4no3 * 6.02×10^23 atom n / 1 mol n =\n1 atom\n6.02×10^23 atoms\n2 atoms\n1.20×10^24 atoms

Answer

Explanation:

Step1: Identify N - atom ratio

In $NH_4NO_3$, there are 2 moles of N atoms per 1 mole of $NH_4NO_3$.

Step2: Use Avogadro's number

1 mole of any substance contains $6.02\times 10^{23}$ entities. For N atoms in 1 mole of $NH_4NO_3$, we multiply the number of moles of N in $NH_4NO_3$ by Avogadro's number. Number of N - atoms = $2\ mol\times6.02\times 10^{23}\ atoms/mol$ $= 1.204\times 10^{24}\ atoms\approx1.20\times 10^{24}\ atoms$

Answer:

1.20 x 10²⁴ atoms