how many protons are there in the isotope represented herein: \n$_{31}^{50}x^{-6}$\n81\n31\n6\n19\n37\n50\n56…
how many protons are there in the isotope represented herein: \n$_{31}^{50}x^{-6}$\n81\n31\n6\n19\n37\n50\n56\n8 multiple choice 10 points\nhow many electrons are there in $^{10}x^{+}$? take the number of neutrons to be 7.\n7\n2\n1\n10\n6
Answer
Explanation:
Step1: Recall proton - atomic number relation
In the isotope notation $_{31}^{50}X^{- 6}$, the sub - script represents the atomic number. The number of protons in an atom is equal to its atomic number.
Step2: Identify the atomic number
The atomic number is 31, so the number of protons is 31.
Answer:
B. 31
Explanation:
Step1: Determine the atomic number
For the ion $^{10}X^{+}$, the mass number is 10. Given the number of neutrons is 7, we can find the atomic number (number of protons) using the formula $mass\ number=number\ of\ protons + number\ of\ neutrons$. So, number of protons $=10 - 7=3$.
Step2: Analyze the charge and electrons
A $+1$ charge means the atom has lost 1 electron. In a neutral atom, number of electrons = number of protons. For $X^{+}$ with 3 protons originally, the number of electrons is $3 - 1=2$.
Answer:
B. 2