3. how many protons, neutrons, and electrons are present in the ¹⁴¹ce⁺⁴ ion? protons = ____ neutrons = ____…
3. how many protons, neutrons, and electrons are present in the ¹⁴¹ce⁺⁴ ion? protons = ____ neutrons = ____ electrons = ____
Answer
Answer:
Protons = 58 Neutrons = 83 Electrons = 54
Explanation:
Step1: Identify atomic number of Ce
The atomic number of cerium (Ce) is 58. Protons equal atomic number, so protons = 58.
Step2: Calculate number of neutrons
Mass - number is 141. Neutrons = mass - number - atomic number. So neutrons = 141 - 58 = 83.
Step3: Calculate number of electrons
The ion is $Ce^{4 + }$. Electrons in neutral atom equal protons (58). For $Ce^{4+}$, electrons = 58 - 4 = 54.