what mass of aluminum sulfate is required to generate 10.0 grams of aluminum phosphate? molar mass alpo₄ =…

what mass of aluminum sulfate is required to generate 10.0 grams of aluminum phosphate? molar mass alpo₄ = 121.95 g/mol molar mass al₂(so₄)₃ = 342.13 g/mol 2na₃po₄ + al₂(so₄)₃ → 2alpo₄(s) + 3na₂so₄ ? g al₂(so₄)₃

what mass of aluminum sulfate is required to generate 10.0 grams of aluminum phosphate? molar mass alpo₄ = 121.95 g/mol molar mass al₂(so₄)₃ = 342.13 g/mol 2na₃po₄ + al₂(so₄)₃ → 2alpo₄(s) + 3na₂so₄ ? g al₂(so₄)₃

Answer

Explanation:

Step1: Calculate moles of ( \text{AlPO}_4 )

Moles = ( \frac{\text{Mass}}{\text{Molar Mass}} ), so moles of ( \text{AlPO}_4 = \frac{10.0\ \text{g}}{121.95\ \text{g/mol}} \approx 0.0820\ \text{mol} )

Step2: Relate moles of ( \text{AlPO}_4 ) to ( \text{Al}_2(\text{SO}_4)_3 )

From the reaction, 2 moles of ( \text{AlPO}_4 ) come from 1 mole of ( \text{Al}_2(\text{SO}_4)_3 ). So moles of ( \text{Al}_2(\text{SO}_4)_3 = \frac{0.0820\ \text{mol}}{2} = 0.0410\ \text{mol} )

Step3: Calculate mass of ( \text{Al}_2(\text{SO}_4)_3 )

Mass = Moles × Molar Mass, so mass = ( 0.0410\ \text{mol} × 342.13\ \text{g/mol} \approx 14.0\ \text{g} )

Answer:

( \approx 14.0\ \text{g} )