what mass of bacl₂ is required to generate 12.0 g baso₄? molar mass baso₄ = 233.39 g/mol molar mass bacl₂ =…

Explanation:

Step1: Calculate moles of BaSO₄

Moles = $\frac{\text{Mass}}{\text{Molar Mass}}$. For BaSO₄, mass is 12.0 g, molar mass is 233.39 g/mol. So moles of BaSO₄ = $\frac{12.0\ \text{g}}{233.39\ \text{g/mol}}$.

Step2: Relate moles of BaCl₂ and BaSO₄

From the reaction, 1 mole of BaCl₂ produces 1 mole of BaSO₄. So moles of BaCl₂ = moles of BaSO₄.

Step3: Calculate mass of BaCl₂

Mass = Moles × Molar Mass. Molar mass of BaCl₂ is 208.23 g/mol. So mass = ($\frac{12.0\ \text{g}}{233.39\ \text{g/mol}}$) × 208.23 g/mol. Calculating: $\frac{12.0\times208.23}{233.39} \approx 10.6\ \text{g}$.

Answer:

10.6 g (or more precisely, after calculation: $\frac{12.0\times208.23}{233.39} \approx 10.6$ g)