what mass of oxygen (o₂) forms in a reaction that forms 15.90 g c₆h₁₂o₆? (molar mass of o₂ = 32.00 g/mol…

what mass of oxygen (o₂) forms in a reaction that forms 15.90 g c₆h₁₂o₆? (molar mass of o₂ = 32.00 g/mol; molar mass of c₆h₁₂o₆ = 180.18 g/mol) 15.90 g c₆h₁₂o₆ = g o₂

what mass of oxygen (o₂) forms in a reaction that forms 15.90 g c₆h₁₂o₆? (molar mass of o₂ = 32.00 g/mol; molar mass of c₆h₁₂o₆ = 180.18 g/mol) 15.90 g c₆h₁₂o₆ = g o₂

Answer

Explanation:

Step1: Calculate moles of $C_6H_{12}O_6$

$n_{C_6H_{12}O_6}=\frac{m_{C_6H_{12}O_6}}{M_{C_6H_{12}O_6}}=\frac{15.90\ g}{180.18\ g/mol}$

Step2: Determine mole - ratio

The balanced chemical equation for the formation of glucose ($C_6H_{12}O_6$) from carbon - dioxide and water (photosynthesis) is $6CO_2 + 6H_2O\rightarrow C_6H_{12}O_6+6O_2$. The mole - ratio of $C_6H_{12}O_6$ to $O_2$ is 1:6. So, $n_{O_2}=6\times n_{C_6H_{12}O_6}$

Step3: Calculate mass of $O_2$

$m_{O_2}=n_{O_2}\times M_{O_2}=6\times\frac{15.90\ g}{180.18\ g/mol}\times32.00\ g/mol$

$m_{O_2}=6\times\frac{15.90\times32.00}{180.18}\ g\approx16.95\ g$

Answer:

16.95