what mass of sodium chloride (nacl) forms when 7.5 g of sodium carbonate (na₂co₃) reacts with a dilute…

what mass of sodium chloride (nacl) forms when 7.5 g of sodium carbonate (na₂co₃) reacts with a dilute solution of hydrochloric acid (hcl)? type in your answer using the correct number of significant figures.\nna₂co₃ + 2 hcl → 2nacl + h₂o + co₂\n7.5 g na₂co₃ = g nacl\ndone

what mass of sodium chloride (nacl) forms when 7.5 g of sodium carbonate (na₂co₃) reacts with a dilute solution of hydrochloric acid (hcl)? type in your answer using the correct number of significant figures.\nna₂co₃ + 2 hcl → 2nacl + h₂o + co₂\n7.5 g na₂co₃ = g nacl\ndone

Answer

Explanation:

Step1: Calculate molar mass of $Na_2CO_3$

The molar mass of $Na$ is approximately $22.99\ g/mol$, $C$ is $12.01\ g/mol$ and $O$ is $16.00\ g/mol$. So molar mass of $Na_2CO_3$ is $2\times22.99 + 12.01+3\times16.00=105.99\ g/mol$.

Step2: Calculate moles of $Na_2CO_3$

Moles of $Na_2CO_3=\frac{mass}{molar\ mass}=\frac{7.5\ g}{105.99\ g/mol}\approx0.0708\ mol$.

Step3: Determine mole - ratio from balanced equation

From the balanced equation $Na_2CO_3 + 2HCl\rightarrow2NaCl + H_2O+CO_2$, the mole - ratio of $Na_2CO_3$ to $NaCl$ is $1:2$.

Step4: Calculate moles of $NaCl$

Moles of $NaCl = 2\times$ moles of $Na_2CO_3=2\times0.0708\ mol = 0.1416\ mol$.

Step5: Calculate mass of $NaCl$

The molar mass of $NaCl$ is $22.99 + 35.45=58.44\ g/mol$. Mass of $NaCl=moles\times molar\ mass=0.1416\ mol\times58.44\ g/mol\approx8.2\ g$.

Answer:

$8.2$