what mass of sodium phosphate is required to generate 10.0 grams of aluminum phosphate? molar mass alpo₄ =…

what mass of sodium phosphate is required to generate 10.0 grams of aluminum phosphate? molar mass alpo₄ = 121.95 g/mol molar mass na₃po₄ = 163.94 g/mol 2na₃po₄ + al₂(so₄)₃ → 2alpo₄(s) + 3na₂so₄ ? g na₃po₄
Answer
Explanation:
Step1: Calculate moles of ( \text{AlPO}_4 )
Moles = ( \frac{\text{mass}}{\text{molar mass}} ), so moles of ( \text{AlPO}_4 = \frac{10.0\ \text{g}}{121.95\ \text{g/mol}} \approx 0.0820\ \text{mol} )
Step2: Relate moles of ( \text{AlPO}_4 ) to ( \text{Na}_3\text{PO}_4 )
From the reaction, ( 2\ \text{mol}\ \text{Na}_3\text{PO}_4 ) produces ( 2\ \text{mol}\ \text{AlPO}_4 ), so mole ratio is ( 1:1 ). Thus, moles of ( \text{Na}_3\text{PO}_4 = 0.0820\ \text{mol} )
Step3: Calculate mass of ( \text{Na}_3\text{PO}_4 )
Mass = moles × molar mass = ( 0.0820\ \text{mol} × 163.94\ \text{g/mol} \approx 13.44\ \text{g} )
Answer:
( 13.4 ) (or more precisely ( 13.44 )) grams of ( \text{Na}_3\text{PO}_4 ) are required.