match the reaction on the right with the corresponding reaction on the left by writing the correct, matching…

match the reaction on the right with the corresponding reaction on the left by writing the correct, matching number in the space provided. solid sodium + chlorine gas → solid sodium chloride solid sodium + liquid water → aqueous sodium hydroxide + hydrogen gas 2h₂(g) + o₂(g) → 2h₂o(g) 2h₂o₂(aq) → o₂(g) + 2h₂o(l) 1) aqueous hydrogen peroxide → oxygen gas + liquid water 2) 2na(s) + cl₂(g) → 2nacl(s) 3) hydrogen gas + oxygen gas → water gas 4) 2na(s) + 2h₂o(l) → 2naoh(aq) + h₂(g)
Answer
Explanation:
Step1: Analyze first left - hand side reaction
The reaction "solid sodium + chlorine gas → solid sodium chloride" is a synthesis reaction. Its balanced chemical equation is $2Na(s)+Cl_2(g)\rightarrow2NaCl(s)$, which matches with option 2 on the right - hand side.
Step2: Analyze second left - hand side reaction
The reaction "solid sodium + liquid water → aqueous sodium hydroxide+hydrogen gas" has the balanced chemical equation $2Na(s)+2H_2O(l)\rightarrow2NaOH(aq) + H_2(g)$, which matches with option 4 on the right - hand side.
Step3: Analyze third left - hand side reaction
The reaction $2H_2(g)+O_2(g)\rightarrow2H_2O(g)$ is the combustion of hydrogen gas to form water vapor. It does not match any of the remaining un - matched reactions on the right in a wrong - match context, but for the sake of the exercise, it is a correct chemical equation for the combination of hydrogen and oxygen to form water.
Step4: Analyze fourth left - hand side reaction
The reaction $2H_2O_2(aq)\rightarrow O_2(g)+2H_2O(l)$ is the decomposition of hydrogen peroxide. It matches with option 1 on the right - hand side.
Answer:
- solid sodium + chlorine gas → solid sodium chloride: 2
- solid sodium + liquid water → aqueous sodium hydroxide + hydrogen gas: 4
- $2H_2(g)+O_2(g)\rightarrow2H_2O(g)$: (already matched in context)
- $2H_2O_2(aq)\rightarrow O_2(g)+2H_2O(l)$: 1