methods of expressing concentration of a solution\n\ng. normality (n)\nfind the normality of the ff:\n- 0.15…

Answer:

• 0.15 M HCl: 0.15 N
• 1.4 M H₂SO₄: 2.8 N
• 2 M NaOH: 2 N
• 0.4 M Ba(OH)₂: 0.8 N

Explanation:

Step1: Recall normality formula

$N = n\times M$, where $n$ is the number of equivalents per mole and $M$ is molarity.

Step2: For HCl

HCl has $n = 1$ (1 H⁺ per molecule), so $N=1\times0.15 = 0.15$ N.

Step3: For H₂SO₄

H₂SO₄ has $n = 2$ (2 H⁺ per molecule), so $N = 2\times1.4=2.8$ N.

Step4: For NaOH

NaOH has $n = 1$ (1 OH⁻ per molecule), so $N=1\times2 = 2$ N.

Step5: For Ba(OH)₂

Ba(OH)₂ has $n = 2$ (2 OH⁻ per molecule), so $N=2\times0.4 = 0.8$ N.