mgo + h₂so₄ → mgso₄ + h₂o\nhow many different elements are there?\nwhat are the products?\nwhat are the…
mgo + h₂so₄ → mgso₄ + h₂o\nhow many different elements are there?\nwhat are the products?\nwhat are the reactions?\nhow many mg atoms are on the product side?\nhow many mg atoms are on the reactant side?\nhow many h atoms are on the product side?\nhow many h atoms are on the reactant side?\nhow many o atoms are on the product side?\nhow many o atoms are on the reactant side?\nhow many s atoms are on the product side?\nhow many s atoms are on the reactant side?\nwhat is the subscript of h on the product side?\nwhat is the subscript of h on the reactant side?\n\np₄ + 3o₂ → p₄o₆\nhow many different elements are there?\nwhat is the product?\nwhat is the reaction?\nhow many p atoms are on the product side?
Answer
Explanation:
For the reaction $MgO + H_2SO_4\rightarrow MgSO_4 + H_2O$:
Step1: Count elements
The elements are Mg, O, H, S. So there are 4 different elements.
Step2: Identify products
The products are $MgSO_4$ and $H_2O$.
Step3: Identify reactants
The reactants are $MgO$ and $H_2SO_4$.
Step4: Count Mg atoms on product - side
In $MgSO_4$, there is 1 Mg atom.
Step5: Count Mg atoms on reactant - side
In $MgO$, there is 1 Mg atom.
Step6: Count H atoms on product - side
In $H_2O$, there are 2 H atoms.
Step7: Count H atoms on reactant - side
In $H_2SO_4$, there are 2 H atoms.
Step8: Count O atoms on product - side
In $MgSO_4$, there are 4 O atoms and in $H_2O$ there is 1 O atom, so a total of 5 O atoms.
Step9: Count O atoms on reactant - side
In $MgO$ there is 1 O atom and in $H_2SO_4$ there are 4 O atoms, so a total of 5 O atoms.
Step10: Count S atoms on product - side
In $MgSO_4$, there is 1 S atom.
Step11: Count S atoms on reactant - side
In $H_2SO_4$, there is 1 S atom.
Step12: Find H sub - script on product - side
In $H_2O$, the sub - script of H is 2.
Step13: Find H sub - script on reactant - side
In $H_2SO_4$, the sub - script of H is 2.
For the reaction $P_4+3O_2\rightarrow P_4O_6$:
Step1: Count elements
The elements are P and O. So there are 2 different elements.
Step2: Identify product
The product is $P_4O_6$.
Step3: Identify reaction type
It is a synthesis reaction (two or more substances combine to form one product).
Step4: Count P atoms on product - side
In $P_4O_6$, there are 4 P atoms.
Answer:
For $MgO + H_2SO_4\rightarrow MgSO_4 + H_2O$:
- How many different elements are there? 4
- What are the products? $MgSO_4$, $H_2O$
- What are the reactants? $MgO$, $H_2SO_4$
- How many Mg atoms are on the product side? 1
- How many Mg atoms are on the reactant side? 1
- How many H atoms are on the product side? 2
- How many H atoms are on the reactant side? 2
- How many O atoms are on the product side? 5
- How many O atoms are on the reactant side? 5
- How many S atoms are on the product side? 1
- How many S atoms are on the reactant side? 1
- What is the subscript of H on the product side? 2
- What is the subscript of H on the reactant side? 2
For $P_4 + 3O_2\rightarrow P_4O_6$:
- How many different elements are there? 2
- What is the product? $P_4O_6$
- What is the reaction? Synthesis reaction
- How many P atoms are on the product side? 4