the molar mass of boron, b, is 10.81 g/mol. how many moles of boron are in 37.8 grams of boron? ? mol b

Answer:

3.497 mol

Explanation:

Step1: Recall mole - mass formula

$n=\frac{m}{M}$ where $n$ is the number of moles, $m$ is the mass and $M$ is the molar mass.

Step2: Identify given values

$m = 37.8\ g$, $M=10.81\ g/mol$

Step3: Substitute values into formula

$n=\frac{37.8\ g}{10.81\ g/mol}\approx3.497\ mol$