the molar mass of copper(ii) chloride (cucl₂) is 134.45 g/mol. how many formula units of cucl₂ are present…

Explanation:

Step1: Calculate moles of CuCl₂

Use the formula $n=\frac{m}{M}$, where $m = 17.6\ g$ (mass) and $M=134.45\ g/mol$ (molar - mass). So, $n=\frac{17.6}{134.45}\ mol$. $n=\frac{17.6}{134.45}\approx0.131\ mol$

Step2: Calculate formula units

Use Avogadro's number $N_A = 6.022\times 10^{23}\ formula\ units/mol$. The number of formula units $N=n\times N_A$. $N = 0.131\times6.022\times 10^{23}$ $N=0.131\times6.022\times 10^{23}\approx7.88\times 10^{22}\ formula\ units$

Answer:

$7.88\times 10^{22}$ formula units