what is the molarity of a solution in which 84.0 grams of sodium chloride, nacl, mm=58.44g/mol is dissolved…

Explanation:

Step1: Calculate moles of NaCl

Use the formula $n=\frac{m}{M}$, where $m = 84.0g$ and $M=58.44g/mol$. So $n=\frac{84.0}{58.44}\ mol$.

Step2: Calculate molarity

The formula for molarity $M=\frac{n}{V}$, with $n=\frac{84.0}{58.44}\ mol$ and $V = 1.25L$. Then $M=\frac{\frac{84.0}{58.44}}{1.25}\ mol/L$. $M=\frac{84.0}{58.44\times1.25}\ mol/L=\frac{84.0}{73.05}\ mol/L\approx1.15mol/L = 1.15M$

Answer:

$1.15M$