the molecule below has 10 $sigma$ bonds. for parts 1 - 4, determine the number of specified orbitals.\n1st…

the molecule below has 10 $sigma$ bonds. for parts 1 - 4, determine the number of specified orbitals.\n1st attempt\npart 1 (1 point)\nhow many of them involve $sp^{3}-s$ orbitals? $sp^{3}-s$ orbitals\npart 2 (1 point)\nhow many involve $sp^{3}-sp^{2}$ orbitals? $sp^{3}-sp^{2}$ orbitals\npart 3 (1 point)\nhow many involve $sp^{2}-sp^{2}$ orbitals? $sp^{2}-sp^{2}$ orbitals\npart 4 (1 point)\nhow many involve $sp^{2}-s$ orbitals? $sp^{2}-s$ orbitals
Answer
Explanation:
Step1: Identify hybrid - ized atoms
Carbon atoms with four single - bonds are $sp^3$ hybridized, carbon atoms with a double - bond are $sp^2$ hybridized, and hydrogen atoms have $s$ orbitals.
Step2: Analyze $sp^3 - s$ bonds
The methyl ($-CH_3$) groups have $sp^3$ hybridized carbon atoms. Each methyl group has three $C - H$ bonds which are $sp^3 - s$ bonds. There are 3 $sp^3 - s$ bonds.
Step3: Analyze $sp^3 - sp^2$ bonds
The bond between the $sp^3$ hybridized carbon of the methyl group and the $sp^2$ hybridized carbon of the carbonyl or alkene - like carbon is 1 $sp^3 - sp^2$ bond. So, there is 1 $sp^3 - sp^2$ bond.
Step4: Analyze $sp^2 - sp^2$ bonds
The $C = C$ double - bond has one $\sigma$ bond which is an $sp^2 - sp^2$ bond, and the $C = O$ double - bond has one $\sigma$ bond which is an $sp^2 - sp^2$ bond. So, there are 2 $sp^2 - sp^2$ bonds.
Step5: Analyze $sp^2 - s$ bonds
The $C - H$ bonds on the $sp^2$ hybridized carbon atoms of the alkene group are $sp^2 - s$ bonds. There are 2 $sp^2 - s$ bonds.
Answer:
Part 1: 3 Part 2: 1 Part 3: 2 Part 4: 2