moles of air\n1.0 mole of h₂ gas fills a flexible container. hydrogen is added until there are 3.0 moles of…

moles of air\n1.0 mole of h₂ gas fills a flexible container. hydrogen is added until there are 3.0 moles of h₂ or the number of moles has tripled.\nthe pressure and temperature of the system are held constant at 800 mm hg and 300 k.\nwhat happens to the volume of this container?\nthe volume is unchanged compared to the original amount.\nthe volume increases to six times the original amount.\nthe volume is reduced to one - third of the original amount.\nthe volume increases to three times the original amount.

moles of air\n1.0 mole of h₂ gas fills a flexible container. hydrogen is added until there are 3.0 moles of h₂ or the number of moles has tripled.\nthe pressure and temperature of the system are held constant at 800 mm hg and 300 k.\nwhat happens to the volume of this container?\nthe volume is unchanged compared to the original amount.\nthe volume increases to six times the original amount.\nthe volume is reduced to one - third of the original amount.\nthe volume increases to three times the original amount.

Answer

Explanation:

Step1: Recall Avogadro's law

At constant temperature and pressure, $V \propto n$ (where $V$ is volume and $n$ is number of moles).

Step2: Analyze the change in moles

Initial moles $n_1 = 1.0$ mole, final moles $n_2=3.0$ moles. The ratio of final - to - initial moles is $\frac{n_2}{n_1}=\frac{3.0}{1.0} = 3$.

Step3: Determine the change in volume

Since $V \propto n$, if $\frac{n_2}{n_1}=3$, then $\frac{V_2}{V_1}=3$ (where $V_1$ is initial volume and $V_2$ is final volume), so $V_2 = 3V_1$.

Answer:

The volume increases to three times the original amount.