6. below is the monomer, \propylene\. show how three of these monomers would be bonded to form a portion of…

6. below is the monomer, \propylene\. show how three of these monomers would be bonded to form a portion of the polymer polypropylene.

6. below is the monomer, \propylene\. show how three of these monomers would be bonded to form a portion of the polymer polypropylene.

Answer

Explanation:

Step1: Understand addition polymerization

Propylene undergoes addition polymerization. In addition polymerization of alkenes, the double - bond breaks and monomers bond together.

Step2: Break the double - bond

The double - bond in propylene ($CH_3CH = CH_2$) breaks to form two free radicals on the carbon atoms that were double - bonded.

Step3: Bond the monomers

The free radicals on the monomers react with each other. The three propylene monomers bond in a head - to - tail fashion. The structure of the trimer (a portion of polypropylene) is $-CH(CH_3)-CH_2-CH(CH_3)-CH_2-CH(CH_3)-CH_2 -$.

Answer:

The structure of the portion of polypropylene formed by three propylene monomers is $-CH(CH_3)-CH_2-CH(CH_3)-CH_2-CH(CH_3)-CH_2 -$