how much of a 0.250 m sucrose solution must be used to prepare 400.0 ml of a 0.0310 m solution?\nml

Explanation:

Step1: Use dilution formula

$M_1V_1 = M_2V_2$ where $M_1$ is the initial molarity, $V_1$ is the initial volume, $M_2$ is the final molarity and $V_2$ is the final volume. We are given $M_1=0.250\ M$, $M_2 = 0.0310\ M$ and $V_2=400.0\ mL$. We need to find $V_1$.

Step2: Rearrange the formula to solve for $V_1$

$V_1=\frac{M_2V_2}{M_1}$ Substitute the given values: $V_1=\frac{0.0310\ M\times400.0\ mL}{0.250\ M}$

Step3: Calculate the value of $V_1$

$V_1=\frac{0.0310\times400.0}{0.250}\ mL=\frac{12.4}{0.250}\ mL = 49.6\ mL$

Answer:

$49.6$