na (aq) + oh (aq) + h (aq) + cl (aq) → na (aq) + cl (aq) + h₂o(l)\npart 3 of 4\nare there any spectator ions…

na (aq) + oh (aq) + h (aq) + cl (aq) → na (aq) + cl (aq) + h₂o(l)\npart 3 of 4\nare there any spectator ions in this reaction?\nyes\nno\npart: 3 / 4\npart 4 of 4\nif you said there are spectator ions in this reaction write the net ionic equation, otherwise write na in the box below.

na (aq) + oh (aq) + h (aq) + cl (aq) → na (aq) + cl (aq) + h₂o(l)\npart 3 of 4\nare there any spectator ions in this reaction?\nyes\nno\npart: 3 / 4\npart 4 of 4\nif you said there are spectator ions in this reaction write the net ionic equation, otherwise write na in the box below.

Answer

Brief Explanations:

Spectator ions are ions that are present in the reaction mixture but do not participate in the actual chemical reaction. In the given equation (Na^{+}(aq)+OH^{-}(aq)+H^{+}(aq)+Cl^{-}(aq)\to Na^{+}(aq)+Cl^{-}(aq)+H_{2}O(l)), we can observe that (Na^{+}) and (Cl^{-}) ions appear on both sides of the equation. This means they do not undergo any chemical change during the reaction, fulfilling the definition of spectator ions.

Answer:

Yes

For the net - ionic equation:

Brief Explanations:

To write the net - ionic equation, we remove the spectator ions ((Na^{+}) and (Cl^{-})) from the total ionic equation. The remaining ions ((H^{+}) and (OH^{-})) react to form water.

Answer:

(H^{+}(aq)+OH^{-}(aq)\to H_{2}O(l))