nahco₃ + hcl → nacl + h₂o + co₂\nmm nahco₃ = 84.01 g/mol\nyou previously determined that a sealed container…

nahco₃ + hcl → nacl + h₂o + co₂\nmm nahco₃ = 84.01 g/mol\nyou previously determined that a sealed container holds 0.0135 moles of co₂ gas. use stoichiometry to calculate the mass of nahco₃ needed to generate the 0.0135 mol co₂.\n? g nahco₃

nahco₃ + hcl → nacl + h₂o + co₂\nmm nahco₃ = 84.01 g/mol\nyou previously determined that a sealed container holds 0.0135 moles of co₂ gas. use stoichiometry to calculate the mass of nahco₃ needed to generate the 0.0135 mol co₂.\n? g nahco₃

Answer

Explanation:

Step1: Determine mole - ratio

From the balanced equation $NaHCO_3 + HCl\rightarrow NaCl + H_2O+CO_2$, the mole - ratio of $NaHCO_3$ to $CO_2$ is 1:1. So, if $n(CO_2)=0.0135$ mol, then $n(NaHCO_3)=0.0135$ mol.

Step2: Calculate mass of $NaHCO_3$

The molar mass of $NaHCO_3$ is $M = 84.01$ g/mol. Using the formula $m=n\times M$, where $n = 0.0135$ mol and $M = 84.01$ g/mol. So, $m(NaHCO_3)=0.0135\times84.01$ g. $m(NaHCO_3)=0.0135\times84.01 = 1.134135\approx1.13$ g

Answer:

$1.13$ g