nahco₃ + hcl → nacl + h₂o + co₂\nnahco₃: 84.01 g/mol\na particular sealed container can hold 0.261 mol co₂…

nahco₃ + hcl → nacl + h₂o + co₂\nnahco₃: 84.01 g/mol\na particular sealed container can hold 0.261 mol co₂ gas. what mass of nahco₃ is needed to generate the co₂?\n? g nahco₃\nhint: use stoichiometry.

nahco₃ + hcl → nacl + h₂o + co₂\nnahco₃: 84.01 g/mol\na particular sealed container can hold 0.261 mol co₂ gas. what mass of nahco₃ is needed to generate the co₂?\n? g nahco₃\nhint: use stoichiometry.

Answer

Explanation:

Step1: Determine mole - ratio

From the balanced chemical equation $NaHCO_3 + HCl\rightarrow NaCl + H_2O+CO_2$, the mole - ratio of $NaHCO_3$ to $CO_2$ is 1:1.

Step2: Calculate moles of $NaHCO_3$

Since the mole - ratio of $NaHCO_3$ to $CO_2$ is 1:1, and the number of moles of $CO_2$ is 0.261 mol, the number of moles of $NaHCO_3$ required, $n_{NaHCO_3}=0.261$ mol.

Step3: Calculate mass of $NaHCO_3$

The molar mass of $NaHCO_3$ is $M = 84.01$ g/mol. Using the formula $m=n\times M$, where $n = 0.261$ mol and $M=84.01$ g/mol. So $m = 0.261\times84.01$ g. $m=0.261\times84.01=21.92661\approx21.9$ g

Answer:

21.9 g