name:____ date:____ find the number of moles in each of the following samples: 1. 1.52 kg of glucose…

name:____ date:____ find the number of moles in each of the following samples: 1. 1.52 kg of glucose ($c_6h_{12}o_6$) 2. 3.2 kg of baking soda ($nahco_3$) 3. 2.75 kg of sugar ($c_{12}h_{22}o_{11}$)

name:____ date:____ find the number of moles in each of the following samples: 1. 1.52 kg of glucose ($c_6h_{12}o_6$) 2. 3.2 kg of baking soda ($nahco_3$) 3. 2.75 kg of sugar ($c_{12}h_{22}o_{11}$)

Answer

Explanation:

Step1: Calculate molar mass of glucose

The molar mass of $C_6H_{12}O_6$: $M_{C_6H_{12}O_6}=(6\times12.01 + 12\times1.01+6\times16.00)\text{ g/mol}=180.18\text{ g/mol}$

Step2: Convert mass of glucose to grams

$m = 1.52\text{ kg}=1.52\times10^{3}\text{ g}$

Step3: Calculate moles of glucose

$n=\frac{m}{M}=\frac{1.52\times 10^{3}\text{ g}}{180.18\text{ g/mol}}\approx8.44\text{ mol}$

Step4: Calculate molar mass of baking - soda

The molar mass of $NaHCO_3$: $M_{NaHCO_3}=(22.99 + 1.01+12.01 + 3\times16.00)\text{ g/mol}=84.01\text{ g/mol}$

Step5: Convert mass of baking - soda to grams

$m = 3.2\text{ kg}=3.2\times10^{3}\text{ g}$

Step6: Calculate moles of baking - soda

$n=\frac{m}{M}=\frac{3.2\times 10^{3}\text{ g}}{84.01\text{ g/mol}}\approx38.1\text{ mol}$

Step7: Calculate molar mass of sugar

The molar mass of $C_{12}H_{22}O_{11}$: $M_{C_{12}H_{22}O_{11}}=(12\times12.01+22\times1.01 + 11\times16.00)\text{ g/mol}=342.34\text{ g/mol}$

Step8: Convert mass of sugar to grams

$m = 2.75\text{ kg}=2.75\times10^{3}\text{ g}$

Step9: Calculate moles of sugar

$n=\frac{m}{M}=\frac{2.75\times 10^{3}\text{ g}}{342.34\text{ g/mol}}\approx8.03\text{ mol}$

Answer:

  1. Approximately 8.44 moles of glucose.
  2. Approximately 38.1 moles of baking - soda.
  3. Approximately 8.03 moles of sugar.