name______ date______ period:______\nelectrons configurations ws\n1. in the following energy levels, circle…

name______ date______ period:______\nelectrons configurations ws\n1. in the following energy levels, circle the sub - levels that are present and cross out the ones that are not:\na. first energy level; n = 1 has\n b. second energy level; n = 2 has\n c. third energy level; n = 3 has\n d. fourth energy level; n = 4 has\n2. how many orbitals are present in the following:\na. first energy level; n = 1 has total orbitals from s =______ p =______ d =______ f =______\nb. second energy level; n = 2 has total orbitals from s =______ p =______ d =______ f =______\nc. third energy level; n = 3 has total orbitals from s =______ p =______ d =______ f =______\nd. fourth energy level; n = 4 has total orbitals from s =______ p =______ d =______ f =______\n3. in the following energy levels, what is the max amount of electrons that can be held in each:\ne. first energy level; n = 1 can hold 2 electrons\nf. second energy level; n = 2 can hold 4 electrons\ng. third energy level; n = 3 can hold 6 electrons\nh. fourth energy level; n = 4 can hold 8 electrons\n4. which sublevel has a dumbbell shape?\na. s sublevel\nb. p sublevel\nc. d sublevel\nd. f sublevel\n5. which sublevels will have the same shape?\na. 2s and 3s\n b. 4p and 4d\n c. 3s and 4d\n d. 4d and 3f\ndraw what the orbital shape would look like...
Answer
Explanation:
Step1: Recall orbital - sub - level rules
The number of orbitals in s sub - level is 1, in p sub - level is 3, in d sub - level is 5 and in f sub - level is 7.
Step2: Determine orbitals for each energy level
- For n = 1, only s sub - level exists. So s = 1, p = 0, d = 0, f = 0, total = 1.
- For n = 2, s and p sub - levels exist. s = 1, p = 3, d = 0, f = 0, total = 1 + 3=4.
- For n = 3, s, p and d sub - levels exist. s = 1, p = 3, d = 5, f = 0, total = 1+3 + 5=9.
- For n = 4, s, p, d and f sub - levels exist. s = 1, p = 3, d = 5, f = 7, total = 1+3 + 5+7 = 16.
Step3: Recall maximum electrons per energy level
The maximum number of electrons in an energy level n is given by 2n².
- For n = 1, 2n²=2(1)² = 2.
- For n = 2, 2n²=2(2)² = 8.
- For n = 3, 2n²=2(3)² = 18.
- For n = 4, 2n²=2(4)² = 32.
Step4: Recall orbital shapes
The p sub - level has a dumb - bell shape.
Step5: Recall same - shaped sub - levels
Sub - levels with the same letter have the same shape. So 2s and 3s have the same shape (spherical).
Answer:
a. s = 1, p = 0, d = 0, f = 0, total = 1 b. s = 1, p = 3, d = 0, f = 0, total = 4 c. s = 1, p = 3, d = 5, f = 0, total = 9 d. s = 1, p = 3, d = 5, f = 7, total = 16 3. e. 2 f. 8 g. 18 h. 32 4. B. p sublevel 5. A. 2s and 3s