what is the net ionic equation for the reaction that is represented by the following total ionic equation…
what is the net ionic equation for the reaction that is represented by the following total ionic equation? 6na⁺ + 2po₄³⁻+3ca²⁺ + 6cl⁻→6na⁺ + 6cl⁻+ca₃(po₄)₂\n2na₃po₄ + 3cacl₂→6nacl + ca₃(po₄)₂\n2po₄³⁻+3ca²⁺→ca₃(po₄)₂\n2po₄³⁻+3ca²⁺ + 6cl⁻→6na⁺ + ca₃(po₄)₂\n2p⁵⁺+8o²⁻+3ca²⁺→ca₃(po₄)₂
Answer
Answer:
B. (2PO_{4}^{3 -}+3Ca^{2 +}\longrightarrow Ca_{3}(PO_{4})_{2})
Explanation:
Step1: Identify spectator ions
Spectator ions are (6Na^{+}) and (6Cl^{-}) as they appear on both sides of the total - ionic equation.
Step2: Write net - ionic equation
Remove spectator ions from the total ionic equation (6Na^{+}+2PO_{4}^{3 -}+3Ca^{2 +}+6Cl^{-}\longrightarrow6Na^{+}+6Cl^{-}+Ca_{3}(PO_{4}){2}), resulting in (2PO{4}^{3 -}+3Ca^{2 +}\longrightarrow Ca_{3}(PO_{4})_{2}).