when one mole of sodium bicarbonate is formed from its elements, 947.7 kj of energy is released into the…

when one mole of sodium bicarbonate is formed from its elements, 947.7 kj of energy is released into the surroundings. this enthalpy change can be represented as a. na(s) + 1/2 h₂(g) + c(s) + 3/2 o₂(g) → nahco₃(s) + 947.7 kj b. na(s) + 1/2 h₂(g) + c(s) + 3/2 o₂(g) → nahco₃(s) - 947.7 kj c. na⁺(aq) + hco₃⁻(aq) → nahco₃(s) + 947.7 kj d. na⁺(aq) + hco₃⁻(aq) → nahco₃(s) - 947.7 kj my answer, including all work:

when one mole of sodium bicarbonate is formed from its elements, 947.7 kj of energy is released into the surroundings. this enthalpy change can be represented as a. na(s) + 1/2 h₂(g) + c(s) + 3/2 o₂(g) → nahco₃(s) + 947.7 kj b. na(s) + 1/2 h₂(g) + c(s) + 3/2 o₂(g) → nahco₃(s) - 947.7 kj c. na⁺(aq) + hco₃⁻(aq) → nahco₃(s) + 947.7 kj d. na⁺(aq) + hco₃⁻(aq) → nahco₃(s) - 947.7 kj my answer, including all work:

Answer

Explanation:

Step1: Identify the reaction of formation of sodium bicarbonate

The formation of sodium bicarbonate from its elements involves the combination of sodium (Na), hydrogen (H₂), carbon (C) and oxygen (O₂) to form NaHCO₃. The enthalpy change of formation is the energy released when one - mole of the compound is formed from its elements in their standard states.

Step2: Analyze the given equations

The correct equation for the formation of sodium bicarbonate from its elements should have the elements on the left - hand side in their standard states and sodium bicarbonate on the right - hand side. The energy released is represented as a positive value on the left - hand side if the reaction is exothermic (which is the case here as energy is released). The standard states of Na is solid (s), H₂ is gas (g), C is solid (s) and O₂ is gas (g). The balanced equation for the formation of one mole of NaHCO₃(s) from its elements is: [Na(s)+\frac{1}{2}H_{2}(g)+C(s)+\frac{3}{2}O_{2}(g)\rightarrow NaHCO_{3}(s)] The energy released is 947.7 kJ, so the correct representation is (Na(s)+\frac{1}{2}H_{2}(g)+C(s)+\frac{3}{2}O_{2}(g)\rightarrow NaHCO_{3}(s)+947.7\ kJ)

Answer:

The correct chemical equation representing the formation of one mole of sodium bicarbonate from its elements with the release of 947.7 kJ of energy is (Na(s)+\frac{1}{2}H_{2}(g)+C(s)+\frac{3}{2}O_{2}(g)\rightarrow NaHCO_{3}(s)+947.7\ kJ)