what is the original concentration of a solution in which 83.5 ml of the concentrated solution is diluted to…
what is the original concentration of a solution in which 83.5 ml of the concentrated solution is diluted to 500. ml of 0.5 m solution?\n? m solution
Answer
Answer:
$3.00\ M$
Explanation:
Step1: Identify dilution formula
$M_1V_1 = M_2V_2$
Step2: Define variables
$M_1$ is unknown, $V_1=83.5\ mL$, $M_2 = 0.5\ M$, $V_2 = 500\ mL$
Step3: Rearrange formula for $M_1$
$M_1=\frac{M_2V_2}{V_1}$
Step4: Substitute values
$M_1=\frac{0.5\ M\times500\ mL}{83.5\ mL}$
Step5: Calculate result
$M_1 = 3.00\ M$