our atmosphere is made up of $78\\% \\text{n}_2$, $21\\% \\text{o}_2$, and $1\\%$ other gases. what is the…

our atmosphere is made up of $78\\% \\text{n}_2$, $21\\% \\text{o}_2$, and $1\\%$ other gases. what is the partial pressure of $\\text{n}_2$ when atmospheric pressure is $0.980 \\text{ atm}$?\n\n$p_{\\text{n}_2} = ? \\text{ atm}$
Answer
Explanation:
Step1: Identify the mole fraction of Nitrogen
The percentage of $N_{2}$ is $78%$, so the mole fraction $\chi_{N_{2}}$ is: $$\chi_{N_{2}} = \frac{78}{100} = 0.78$$
Step2: Apply Dalton's Law of Partial Pressures
The partial pressure $P_{N_{2}}$ is the product of mole fraction and total pressure $P_{total}$: $$P_{N_{2}} = \chi_{N_{2}} \times P_{total}$$
Step3: Calculate the final value
Substitute $0.78$ for $\chi_{N_{2}}$ and $0.980\text{ atm}$ for $P_{total}$: $$P_{N_{2}} = 0.78 \times 0.980\text{ atm} = 0.7644\text{ atm}$$
Answer:
$P_{N_{2}} = 0.7644\text{ atm}$